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can you help me? im so confused

Can You Help Me Im So Confused class=

Sagot :

Answer:

(AB) is longer than (AC)

Step-by-step explanation:

1. Approach

Use the distance formula to find the length of the segments (AC) and (AB); substitute their endpoints into the distance formula and simplifying to solve for the length. After finding the length of each segment, compare their lengths to find out which of the statements is true. The distance formula is as follows:

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Where ([tex](x_1,y_1)[/tex]) and ([tex](x_2,y_2)[/tex]) are the endpoints of the segment.

2. Find the length of (AC)

Coordinates of point (A): [tex](-1,1)[/tex]

Coordinates of point (C): [tex](-4,4)[/tex]

Substitute these points into the distance formula,

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]D=\sqrt{((-1)-(-4))^2+((1)-(4))^2}[/tex]

Simplify,

[tex]D=\sqrt{((-1)-(-4))^2+((1)-(4))^2}[/tex]

[tex]D=\sqrt{(-1+4)^2+(1-4)^2}[/tex]

[tex]D=\sqrt{(3)^2+(-3)^2}[/tex]

[tex]D=\sqrt{9+9}[/tex]

[tex]D=\sqrt{18}[/tex]

3. Find the length of (AB)

Coordinates of point (A): [tex](-1,1)[/tex]

Coordinates of point (B): [tex](0,-4)[/tex]

Substitute these points into the distance formula,

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]D=\sqrt{((-1)-(0))^2+((1)-(-4))^2}[/tex]

Simplify,

[tex]D=\sqrt{((-1)-(0))^2+((1)-(-4))^2}[/tex]

[tex]D=\sqrt{(-1-0)^2+(1+4)^2}[/tex]

[tex]D=\sqrt{(-1)^2+(5)^2}[/tex]

[tex]D=\sqrt{1+25}[/tex]

[tex]D=\sqrt{26}[/tex]

4. Find the correct statement

(AB) is longer than (AC)

This statement is true for the following reason:

[tex]\sqrt{18}>\sqrt{26}[/tex]

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