Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

A 6.0-L vessel was found to contain 1.0 mol BrCl 3 , 2.0 mol Br 2 and 6.0 mol Cl 2 at equilibrium. What is the equilibrium constant, K c , for this equilibrium mixture for the reaction 2BrCl 3 (g) Br 2 (g) 3Cl 2 (g)

Sagot :

spectrojamz

Answer:

Writing a balanced Equation for the reaction

Br₂ + 3Cl₂ ==> 2BrCl₃

Kc = [BrCl₃]² / [Br₂][Cl₂]³

Each Concentration (n) = moles/volume of container.

(nBrCl₃)= 1/6 = 0.167moldm-³

(nBr₂) = 2/6 = 0.333moldm-³

(nCl₂) = 6/6 = 1moldm-³

Kc = (0.167)² / (0.333)(1)³

Kc = 0.0838.

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.