Answer:
11.31 units
Step-by-step explanation:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Step 1.
Plug in the points inside the formula where the first point = [tex](x_1,y_1)[/tex] and the second point = [tex](x_2-y_2)[/tex]
Let the first point be C and the second point be D
[tex](-4,-5)\\ (x_1,y_1)[/tex] [tex](4,3)\\ (x_2,y_2)[/tex]
Answer: [tex]d=\sqrt{(4--4)^2+(3--5)^2}[/tex]
Step 2. Simplify the parentheses "( )"
Answer: [tex]d=\sqrt{(8^2)+(8^2)}[/tex]
Step 3. Simplify the exponents "[tex]?^2[/tex]"
Answer: [tex]d=\sqrt{64 +64}[/tex]
Step 4. Add 64 and 64
Answer: [tex]d=\sqrt{128}[/tex]
Step 5. Simplify the square root
Answer: [tex]d=11.31[/tex]
Therefore, the distance between points C and D is 11.31 units
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