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A ball is thrown straight up into the air from an initial height of 5 feet at time t = 0. The height, in feet, of the ball above the ground is given by h(t), where t is measured in seconds for 0 ≤ t ≤ 15. Based on the values of t and h(t) given in the table, for which value of t would the speed of the ball most likely be the greatest?

t (seconds) 0 3 6 9 12 15
h(t) (feet) 5 12 15 11 6 0

Select one:
a. 2 seconds
b. 5 seconds
c. 9 seconds
d. 15 seconds

Sagot :

Answer:

5 seconds

Step-by-step explanation:

The speed of an object is the rate of distance over time. The value of time (t) at the greatest speed of the ball is at 2 seconds

First, we calculate the speed using:

[tex]Speed = \frac{h(t)}{t}[/tex] --- i.e. distance/time

At t = 0, h(t) = 5

So;

[tex]Speed = \frac{5}{0} = unde fine d[/tex]

At t = 3, h(t) = 12

[tex]Speed = \frac{12}{3} = 4[/tex]

At t = 6, h(t) = 15

[tex]Speed = \frac{15}{6} = 2.5[/tex]

At t = 9, h(t) = 11

[tex]Speed = \frac{11}{9} = 1.2[/tex]

At t = 12, h(t) = 6

[tex]Speed = \frac{6}{12} = 0.5[/tex]

At t = 15, h(t) = 0

[tex]Speed = \frac{0}{15} = 0[/tex]

By comparing the above values, we notice that as time and height increases, the value of speed reduces.

This means that the greatest value of speed will be at the least value of time (t).

From the given options, the least value of time is at:

[tex]t = 2[/tex]

Hence, the value of time (t) at the greatest speed of the ball is at 2 seconds

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