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Sagot :
Answer: 3468
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Work Shown:
a = first term = 3
d = common difference = 6
S(n) = sum of the first n terms of an arithmetic sequence
S(n) = (n/2)*(2a + d(n-1))
S(34) = (34/2)*(2*3 + 6(34-1))
S(34) = 3468
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Check:
3+9+15+21+27+33+39+45+51+57+63+69+75+81+87+93+99+105+111+117+123+129+135+141+147+153+159+165+171+177+183+189+195+201 = 3468
I used GeoGebra to generate the 34 terms shown above. You could do so by hand (start at 3; add 6 to each term to get the next one), but it's a tedious busywork type of problem in my opinion. It's best left to computer software.
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