Answered

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how would I solve this and what is the answer.

How Would I Solve This And What Is The Answer class=

Sagot :

Answer:

b is -6 or -10

Step-by-step explanation:

[tex] \frac{1}{b} = \frac{1}{b - 12} + \frac{ {b}^{2} + 16b + 48}{ {b}^{2} - 12b} \\ \\ \frac{1}{b} = \frac{b + ( {b}^{2} + 16b + 48)}{b(b - 12)} \\ \\ b - 12= b + ( {b}^{2} + 16b + 48) \\ {b}^{2} + 16b + 60= 0 \\ (b + 6)(b + 10) = 0 \\ b = - 6 \\ and \\ b = - 10[/tex]

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