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Sagot :
I’m not sure if I’m right
c(1)=c
cx1=c
c(n)=c(n-1)=c=0, n€R
cn=cx(n-1)
nc=cx(n-1)
nc=nc-c
0=-c
-c=0
c=0
c=0, n€R
hope this helps
c(1)=c
cx1=c
c(n)=c(n-1)=c=0, n€R
cn=cx(n-1)
nc=cx(n-1)
nc=nc-c
0=-c
-c=0
c=0
c=0, n€R
hope this helps
C(1)=c the absolute value of any number is always positive and any expression multiple by 1 remains the same c(n) = (n-1) c=0. Hopes that helps
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