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A scientist started with a sample of 8 cells. The sample increased as shown in the table.



Assume that the pattern in the table continues. Which equation can be solved for t, the time in hours when the number of cells will reach 100,000?

A
8⋅t4=100,000

B
8⋅4t=100,000

C
4⋅t8=100,000

D
4⋅8t=100,000


A Scientist Started With A Sample Of 8 Cells The Sample Increased As Shown In The Table Assume That The Pattern In The Table Continues Which Equation Can Be Sol class=

Sagot :

Answer:

100000 = 8 (4) ^t

Step-by-step explanation:

We are multiplying by 4 each time

y = a (4)^t

The initial amount is 8

y = 8 (4)^t

We want to get to 100000

100000 = 8 (4) ^t

Answer:

B

8 ⋅ 4^t  = 100,000

Step-by-step explanation:

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