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Answered

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Help Pleaseeeeeeeeee class=

Sagot :

caylus

Answer:

Hello,

Answer D

Step-by-step explanation:

I suppose that i is the imaginary (i²=-1)

i^4=1

i^99=i^(4*24+3)=i^3

i^3-i^3=0

Answer D

Answer:  D)  0

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Explanation:

Take note of this pattern

  • i^0 = 1
  • i^1 = i
  • i^2 = -1
  • i^3 = -i
  • i^4 = 1

After this point, we repeat the cycle. The cycle is 4 units long. This means we can divide the exponent over 4 and look at the remainder

99/4 = 24 remainder 3

So i^99 = i^3

which means i^99 - i^3 = i^3 - i^3 = 0

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