sfaith993
Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

help me pleasssseeeeeee

Help Me Pleasssseeeeeee class=

Sagot :

Answer:

[tex]{ \bf{b. \: \: {i}^{47} }}[/tex]

Step-by-step explanation:

[tex] {i}^{46} = ( {i}^{2} ) {}^{23} = - 1 \\ \\ {i}^{47} = (i)( {i}^{46} ) = ( - 1 \times i) = - i \\ \\ {i}^{48} = ( {i}^{2} ) {}^{24} = 1 \\ \\ {i}^{49} = (i)( {i}^{48}) = (1 \times i) = i[/tex]

Answer:

[tex]i^{46} = -i[/tex]

~~~~~~~~~~~~~~~~~~~

46/4 = 11 remainder 2 = [tex]-i[/tex]

47/4 = 11 remainder 3 = 1

48/4 = 11 remainder 0 =  [tex]i[/tex]

49/4 = 11 remainder 1 = -1

Step-by-step explanation:

[tex]i = \sqrt{-1} = i[/tex]  (remainder 0)

[tex]i^{2} = \sqrt{-1} * \sqrt{-1} = -1[/tex] (remainder 1)

[tex]i^{3} = \sqrt{-1} * \sqrt{-1} * \sqrt{-1}= -1 * \sqrt{-1} = -i[/tex] (remainder 2)

[tex]i^{4} = \sqrt{-1} * \sqrt{-1} * \sqrt{-1} * \sqrt{-1}= -1 * -1 = 1\\[/tex] (remainder 3)

[tex]i^{5} = \sqrt{-1} * \sqrt{-1} * \sqrt{-1} * \sqrt{-1}* \sqrt{-1}= 1 * \sqrt{-1} = i\\[/tex] (remainder 0)

The pattern repeats every FOUR in the exponent

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.