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Sagot :
Answer:a0 = 40 mg
a1 = 20 mg after 28 years
a2 = 10 mg after another 28 years
Step-by-step explanation:Set this up as
10 = 40 (1/2)t/28
and solve for t in years.
10/40 = (1/2)t/28
log(0.25) = (t/28) log(0.5)
t = 28 log(0.25) / log(0.5) years = 56 years
Answer:
40 mg
Step-by-step explanation:
10 = 40 (1/2)t/28 and solve for t in years. 10/40 = (1/2)t/28 log(0.25) = (t/28) log(0.5) t = 28 log(0.25) / log(0.5) years = 56 years
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