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Sagot :
Using a system of equations, it is found that:
- There are 8 chickens in the yard.
- There are 16 pigs in the yard.
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This question is solved using a system of equations. I am going to say that:
- x is the number of chickens.
- y is the number of pigs.
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- A chicken has 1 head, as do a pig.
- There are 24 heads.
Thus:
[tex]x + y = 24 \rightarrow y = 24 - x[/tex]
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- A chicken has 2 feet.
- A pig has 4 feet.
- In total, there are 80 feet.
Thus:
[tex]2x + 4y = 80[/tex]
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Number of chicken:
Since [tex]y = 24 - x[/tex]
[tex]2x + 4y = 80[/tex]
[tex]2x + 4(24 - x) = 80[/tex]
[tex]2x + 96 - 4x = 80[/tex]
[tex]2x = 16[/tex]
[tex]x = \frac{16}{2}[/tex]
[tex]x = 8[/tex]
There are 8 chickens in the yard.
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Number of pigs:
[tex]y = 24 - x = 24 - 8 = 16[/tex]
There are 16 pigs in the yard.
A similar problem is given at https://brainly.com/question/24104709
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