dancezepeto31
Answered

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prove that is here
[tex]1 - cos {2}a \div 1 - sin a{2} = tan {2} a[/tex]
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Sagot :

[tex]\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}[/tex]

LHS

[tex]\boxed{\sf \dfrac{cosA}{sinA}=cotA}[/tex]

[tex]\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}[/tex]

[tex]\\ \sf\longmapsto 1-cot2A[/tex]

[tex]\\ \sf\longmapsto 1-\dfrac{1}{tan2A}[/tex]

[tex]\\ \sf\longmapsto \dfrac{tan2A-1}{tan2A}[/tex]

[tex]\\ \sf\longmapsto tan2A[/tex]

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