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If y varies inversely with the square of x, and y = 26 when x = 4, find y when x = 2.

A. 13
B. 52
C. 208
D. 104


Sagot :

Answer:

D. 104

Step-by-step explanation:

[tex]y \: \alpha \: \frac{1}{ {x}^{2} } \\ \\ y = \frac{k}{ {x}^{2} } [/tex]

when y is 26, x is 4:

[tex]26 = \frac{k}{ {(4)}^{2} } \\ k = 416[/tex]

when x is 2:

[tex]y = \frac{416}{ {x}^{2} } \\ \\ y = \frac{416}{ {(2)}^{2} } \\ y = 104[/tex]

Answer:

D; 104

This is the correct answer

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