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Given that for the water leakage n=100 Σx=31,353 and Σx^2 = 10687041 calculate the simple mean.​

Sagot :

Answer:

[tex] \bar x = \frac{ \sum x}{n} \\ \\ \bar x = \frac{31353}{100} \\ \\ \bar x = 313.53[/tex]

caylus

Answer:

Hello,

Step-by-step explanation:

[tex]n=100\\\\\displaystyle \sum_{i=1}^{100}x_i=31.353\\\\\\\overline{x}=\dfrac{\displaystyle \sum_{i=1}^{100}x_i}{n} =\dfrac{31.353}{100} =\boxed{0.31353}\\\\[/tex]