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(08.02 MC)
What is the molarity of a solution prepared by dissolving 20.0 grams of NaOH in sufficient water to make a solution with a
total volume of 2.40 liters? (5 points)
Select one:
a.0.120 M NaOH
6.0.208 M NaOH
c.0.416 M NaOH
O
d.0.833

Sagot :

starsr616

Answer:

d. 0.208 M NaOH

Explanation:

M[NaOH] = 23+16+1= 40g/mol

2.40L = 2.4dm3

M=m/Mv

M=20.0g/40g/mol×2.4dm3

M=20.0g ÷ 96

M= 0.208 M NaOH

The statement of the molarity of a solution is "0.208 M NaOH."

What is molarity?

The amount of a chemical substance in a defined volume of the solution is measured in molarity (M). The moles of a solute per litre of a solution is known as molarity. The molar concentration of a solution is also known as molarity.

In order to determine the molarity, initially calculate the number of moles of sodium hydroxide by dividing the given mass by molar mass of NaOH.

Gram to mole conversion factor,

Moles of NaOH

[tex]= (20.0\;g) * \frac{(1\;mol\;NaOH)}{(39.998\;g)} \\= 0.50\;mol[/tex]

Now, the molarity of the solution comes out to be,

[tex]Molarity = \frac{Moles\;of\;the\;solute}{Volume\;of\;the\;solution}[/tex]

So,

[tex]= \frac{0.0500 \;mol}{2.40\;L} \\= 0.208\;\frac{mol}{L} = 0.208\;M[/tex]

Hence the correct option is b.

Learn more bout molarity here

https://brainly.com/question/11386850

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