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Given: △PST, Area of △PST=71.24 PS=15, Pt=13 Find: m∠P (Please help!!!)

Sagot :

Answer:

∠ P ≈ 46.9°

Step-by-step explanation:

The area (A) of Δ PST is calculated as

A = [tex]\frac{1}{2}[/tex] × PS × PT × sinP

Here A = 71.24 , then

[tex]\frac{1}{2}[/tex] × 15 × 13 × sinP= 71.24 , that is

97.5 × sinP = 71.24 ( divide both sides by 97.5 )

sinP = [tex]\frac{71.24}{97.5}[/tex] , then

∠ P = [tex]sin^{-1}[/tex] ([tex]\frac{71.24}{97.5}[/tex] ) ≈ 46.9° ( to the nearest tenth )

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