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Sagot :
Answer:
(x-3)^2 = 5
x = 3 ±sqrt(5)
Step-by-step explanation:
x ^2 −4x+4=2x
Subtract 2x from each side
x ^2 −4x-2x+4=2x-2x
x^2 -6x +4 = 0
Subtract 4 from each side
x^2 -6x+4-4 =0-4
x^2 -6x = -4
Take -6
Divide by 2
-6/2 = -3
Square it
(-3)^2 = 9
Add to each side
x^2 -6x+9 = -4+9
(x-3)^2 = 5
Take the square root
sqrt((x-3)^2) = ±sqrt(5)
x-3 = ±sqrt(5)
Add 3 to each side
x = 3 ±sqrt(5)
Answer:
lusing completing square metjod
x
Step-by-step explanation:
x^2_6x+(_3)^2=_4+9
(x_3)^2=5
x_3=
[tex] \sqrt{5} [/tex]
[tex]x = 3 + or - \sqrt{5} [/tex]
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