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Determine the vertex of the function f(x) = 3(x - 2)^2 + 1.
(2, 1)
(-2, 1)
(1,2)
(1,-2)


Sagot :

Answer:

The vertex is at (2,1)

Step-by-step explanation:

The vertex form of a quadratic is

y = a(x-h)^2 +k  where (h,k) is the vertex

f(x) = 3(x - 2)^2 + 1.

The vertex is at (2,1)