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Sagot :
Answer:
[tex]x + a = \frac{3}{4} \\ x = \frac{3}{4} - a[/tex]
for a:
[tex]a = \frac{3}{4} - x[/tex]
[tex]\\ \sf \longmapsto x+a=\dfrac{3}{4}[/tex]
[tex]\\ \sf \longmapsto x=\dfrac{3}{4}-a[/tex]
[tex]\\ \sf \longmapsto x=\dfrac{3-4a}{4}[/tex]
And
[tex]\\ \sf \longmapsto a=\dfrac{3}{4}-x[/tex]
[tex]\\ \sf \longmapsto a=\dfrac{3-4x}{4}[/tex]
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