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X+a=3/4
How do I solve for x first then a


Sagot :

Answer:

[tex]x + a = \frac{3}{4} \\ x = \frac{3}{4} - a[/tex]

for a:

[tex]a = \frac{3}{4} - x[/tex]

[tex]\\ \sf \longmapsto x+a=\dfrac{3}{4}[/tex]

[tex]\\ \sf \longmapsto x=\dfrac{3}{4}-a[/tex]

[tex]\\ \sf \longmapsto x=\dfrac{3-4a}{4}[/tex]

And

[tex]\\ \sf \longmapsto a=\dfrac{3}{4}-x[/tex]

[tex]\\ \sf \longmapsto a=\dfrac{3-4x}{4}[/tex]