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Sagot :
The question is solved using the equations of motion
According to the equations of motion:
[tex]v^2 = u^2 -2gh[/tex]
v = final velocity
u = initial velocity
g = acceleration due to gravity
h = height
Note that at the maximum height, the final velocity (v) = 0 m/s
so we can write:
[tex]u^2 = 2gh[/tex]
[tex]h = \frac{u^2}{2gh}[/tex][tex]h= \frac{100^2}{2 * 10}[/tex]
h = 500 m
The time taken is obtained from:
[tex]v= u - gt[/tex]
since v= 0 at maximum height
[tex]u = gt\\\\t= u/g\\\\t= 100/10\\t = 10 s[/tex]
For more about equations of motion, see
https://brainly.com/question/20594939
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