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A projectile is fired vertically upward at an initial velocity of 100 m/s. How high will it rise? How long will it take to reach that height?

Sagot :

The question is solved using the equations of motion

According to the equations of motion:

[tex]v^2 = u^2 -2gh[/tex]

v = final velocity

u = initial velocity

g = acceleration due to gravity

h = height

Note that at the maximum height, the final velocity (v) = 0 m/s

so we can write:

[tex]u^2 = 2gh[/tex]

[tex]h = \frac{u^2}{2gh}[/tex][tex]h= \frac{100^2}{2 * 10}[/tex]

h = 500 m

The time taken is obtained from:

[tex]v= u - gt[/tex]

since v= 0 at maximum height

[tex]u = gt\\\\t= u/g\\\\t= 100/10\\t = 10 s[/tex]

For more about equations of motion, see

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