Textmedoni
Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A tank of water holding 528 kl of water begain to empty at a rate of 10 kl/min at the same time a another tank whitch is empty begins to fill at a rate of 14kl/min let k repreasens the number of kiloliters of water and let t repreasent time in min the system models the solution

How long will it take for each tank to have the Same amount of water , and how much water will that be

It will take __minitutes for both tanks to hold equal amounts of water . They will each hold ___ kiloliters.

Sagot :

thisisbenmanley
This is a system of equations.  The first equation represents the tank being emptied and the second equation represents the tank being filled:

k = -10t + 528
k = 14t

To solve this system of equations, we will use substitution. The second equation says that k is equal to 14t, so we can substitute 14t for k in the first equation.

14t = -10t + 528
24t = 528
t = 22

Now that we have t, we can use it to find k by plugging it in to the second equation:

k = 14(22)
k = 308

So, it will take 22 minutes for both tanks to hold equal amounts of water. They will each hold 308 kiloliters.
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.