angelvelasco123
Answered

Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

what is the vertex of the graph of the equation y = 3x²+6x+1?

Sagot :

luana
[tex]y=3x^2+6x+1\\\\V(-\frac{b}{2a},-\frac{\Delta}{4a})\\\\-\frac{b}{2a}=-\frac{6}{2\cdot3}=-\frac{6}{6}=-1\\\\\Delta=6^2-4\cdot3\cdot1=36-12=24\\\\-\frac{\Delta}{4a}=-\frac{24}{4\cdot3}=-\frac{24}{12}=-2\\\\V(-1,-2)[/tex]
logo88
y=3x²+6x+1
to find the x value of the vertex, find the axis of symmetry which is -b/2a where a=3 and b=6,
so the axis of symmetry
=-6/2(3)
=-1
to find the y value of the vertex sub the axis of symmetry which is -1 back into the original equation. 
y= 3(-1)²+6(-1)+1
y=-2

therefore the vertex is (-1,-2) 


Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.