Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

i need 23, 28, and 40 desperately

Take the digits 5, 4, 3, 2 and 1, in that order. Using those digits and the four arithmetic signs — plus, minus, times and divided by — you can get 1 with the sequence 5 - 4 + 3 - 2 - 1. You can get 2 with the sequence (5 - 4 + 3 - 2) x 1.

The question is ... how many numbers from 1 to 40 can you get using the digits 5, 4, 3, 2, and 1 in that order along with the four arithmetic signs?

You can group digits with parentheses, as in the example. There are no tricks to this, though. It's a straightforward puzzle. How many numbers from 1 to 40 can you get — and, specifically, what number or numbers can you not get?

Sagot :

sqdancefan

9514 1404 393

Answer:

  • (5 +4 +3)×2 -1 = 23
  • 5 +(4×3×2) -1 = 28
  • 5×(4 +3 +2 -1) = 40

Step-by-step explanation:

The above expressions give the values you requested. I was able to form all integers 1-40 except 39.

_____

Additional comment

I used a computer program to evaluate different sequences of operations. Attached is one result for each integer 1-40 except 39. The notation here is postfix, but is not difficult to translate to infix with parentheses. Starting with the left-most operation (op), the pattern (a, b, op) → (a op b) is used. For example, the listing for 38 is 543+*21++, so this becomes 5*(4+3)+(2+1) = 38.

View image sqdancefan
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.