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Calculate the corresponding weights of liquefied phenol and propylene glycol needed to prepare 24 15 ML - bottles of the following formula for a cood sore topical liquid:
liquefied phenol 0,4 mL
camphor 0,5 g
Benzocaine 2,2 g
Ethanol 65 mL
Propylene glycol 17 mL
Purified water ad 100 mL​

Sagot :

batolisis

Mass/corresponding weight of liquefied phenol = 1.5408 grams

Mass/corresponding weight of propylene glycol = 63.6 grams

Given that :

Total volume of the water bottles = 24 * 15 ml

                                                        = 360 ml

Volume of recipe after pure water is added = 100 ml

the number of units required = Total volume of water / volume of recipe

                                                = 360 / 100 =  3.6 units

i) Determine the Mass ( weight ) of liquefied phenol

amount of liquefied phenol = 0.4 ml * 3.6 = 1.44 ml

given that density of liquefied phenol = 1.07 g/ml

∴ mass of liquefied phenol = density * volume

                                         = 1.07 * 1.44 = 1.5408 grams

ii) Mass( weight ) of propylene glycol

amount = 17 * 3.6 =  61.2 ml

density of propylene glycol = 1.04 g/ml

∴ mass of propylene glycol = 61.2 * 1.04 = 63.648 grams

learn more : https://brainly.com/question/24469158

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