Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Answer:
1
[tex]g(n) = 2 + {(n + 2)}^{3} [/tex]
let the inverse be m :
[tex]m = 2 + {(n + 2)}^{3} \\ {(n + 2)}^{3} = m - 2 \\ n + 2 = \sqrt[3]{(m - 2)} \\ n = \{ \sqrt[ 3]{(m - 2)} - 2 \}[/tex]
therefore:
[tex]{ \boxed{ \boxed{g {}^{ - 1}(n) = \{ \sqrt[3]{(n - 2)} - 2 \}}}}[/tex]
2.
[tex]f(n) = \frac{1}{2} n + \frac{3}{2} [/tex]
let inverse be x :
[tex]x = \frac{1}{2} n + \frac{3}{2} \\ \\ 2x = n + 3 \\ n = 2x - 3[/tex]
therefore:
[tex]{ \boxed{ \boxed{f {}^{ - 1}(n) = 2n - 3 }}}[/tex]
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
