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Write an equation in slope-intercept form for the line that passes through point (2, -1) and is parallel to the line described y = (2/3)x - 6

Sagot :

Theekshana

Answer:

[tex]y=\frac{2}{5}x-5[/tex]

Step-by-step explanation:

[tex]\\y=\frac{2}{3}x-6[/tex]

the line parallel  to this line is

[tex]y=\frac{2}{3}x+k[/tex] ; k ∈ R

the line passes through the point (2,-1)

so,

[tex]-1=\frac{2}{3} (2)+k\\-1=\frac{4}{3} +k\\k=-\frac{7}{3}[/tex]

∴the line that passes through point (2, -1) and is parallel to the line described y = (2/3)x - 6 is

[tex]y=\frac{2}{3}x-\frac{7}{3}[/tex]

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