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Sagot :
9514 1404 393
Answer:
(B) 4
Step-by-step explanation:
Consider the units column. The only sum of 3 and a single digit that will end in 1 is the sum ...
3 + 8 = 11
This tells you A = 8, so the top number is 1983, and the middle number is B78.
Considering the first two columns, we know that 83 +78 = 161, so there must be a carry of 1 into the third column. That makes it have the sum ...
1 + 9 + B = <something ending in 4>
We know the something cannot be 04 or 24, so must be 14. Then ...
10 + B = 14 ⇒ B = 4
__
So, the whole sum is ...
1983 +478 = 2461
and the letter values are ...
- A = 8
- B = 4
- D = 2
Answer:
B is 4.
Step-by-step explanation:
If we start by the ones place and add we know that to get a one the total must be 11. 11-3 = 8. Therefore A = 8.
Now we move to the tens place, since we know A is 8 we can substitute it there. Don't forget to add the one from the 11 we got. 1+8+7 = 16
Now we move to the hundreds place and we carry our one from 16 so now it's 1 + 9 + ? = 4, if we know that our total needs to be 14 in order to have the 4 there- 1 + 9 is 10 we can do 10 + 4 and that gets us 14. So B is 4.
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