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A wheelbarrow of mass 20 kg accelerates from rest and reaches speed of 10m/S2 in 5 seconds.its force?​

Sagot :

Answer:

[tex]\boxed {\boxed {\sf 40 \ Newtons}}[/tex]

Explanation:

We are asked to find the force of a wheelbarrow. According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F= \ m \times a[/tex]

1. Calculate Acceleration

The mass of the wheelbarrow is 20 kilograms. We are not given the acceleration, so we must calculate it using the following formula.

[tex]a= \frac{v_f-v_i}{t}[/tex]

The wheelbarrow starts at rest or 0 meters per second (initial velocity) and accelerates to reach 10 meters per second (final velocity) in 5 seconds (time).

  • [tex]v_f=[/tex]10 m/s
  • [tex]v_i=[/tex]0 m/s
  • t= 5 s

Substitute these values into the formula.

[tex]a= \frac{ 10 \ m/s-0 \ m/s}{5 \ s}[/tex]

Solve the numerator.

[tex]a= \frac{10 \ m/s}{5 \ s}[/tex]

Divide.

[tex]a= 2 \ m/s/s[/tex]

[tex]a= 2 \ m/s^2[/tex]

2. Calculate Force

Now we know the mass and acceleration of the wheelbarrow

  • m= 20 kg
  • a= 2 m/s²

Substitute the values into the force formula.

[tex]F= 20 \ kg \times 2 \ m/s^2[/tex]

[tex]F= 40 \ kg*m/s^2[/tex]

Convert the units. 1 kilogram meter per square second is equal to 1 Newton, so our answer of 40 kilogram meters per square second is equal to 40 Newtons.

[tex]F= 40 \ N[/tex]

Answer:

40 N

Explanation:

We know that

F = ma

and

a = (v - u)/t

So,

F = m(v - u)/t

F = 20(10 - 0)/5

F = 20(10/5)

F = 20(2)

F = 40 N