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Using the average experimental value for the density of your unknown metal, calculate the
agine a large sample of the same metal weighed 950 pounds. Calculate as volume in cubic meters using
dimensional analysis fie, use conversion factors and show unit cancellation. Start with 950 lbs...)

Sagot :

Unit conversion using dimensional analysis is performed by multiplying the given unit with the conversion factor

The volume of a 2 ft.³ in cubic meters is approximately 0.056634 m³

The given mass of the sample of metal, m = 950 pounds

The units of density using the imperial units = [tex]lb_m[/tex]/ft.³

The units of the volume of the metal sample based on the above density = Cubic feet

The desired units = Cubic meters

The conversion factor for converting a unit in cubic feet to a unit in cubic meters is presented as follows

1 ft.³ = 0.0283 m³

Therefore, using dimensional analysis, the volume quantity in cubic feet is multiplied by 0.0283 m³/(1 ft.³) to convert the volume to cubic meters

Example;

Given that the volume of the metal sample 2 ft.³, we have that the volume in cubic meters is therefore;

2 ft.³ × (0.0283 m³)/(1 ft.³) ≈ 0.056634 m³

The volume of a sample of metal that is 2 ft.³ in cubic meters is ≈ 0.056634 m³

Learn more about dimensional analysis here:

https://brainly.com/question/22015862

https://brainly.com/question/17224555

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