Answered

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What is the equation of the line that is perpendicular to
the given line and has an x-intercept of 6?
4
O y=-3x+8
O x
y=-3x+6
O y= x - 8
Oy= x-6

Sagot :

angelinavs92

Answer:

y= x-6

Step-by-step explanation:

View image angelinavs92

The equation of the line that is perpendicular to the given line and has an x-intercept of 6 is y = [tex]\frac{4}{3}x-8[/tex]

Perpendicular lines

Perpendicular lines follows the mathematical principle.

  • m₁m₂ = -1

where

m₁ and m₂ are slopes of the lines.

A line that has a x - intercept of 6 and perpendicular to the given line can be represented as follows.

y = mx + b

where

m = slope

b = y-intercept

(-4, 4)(4, -2)

m = -2 - 4 / 4 + 4 = -6 / 8 = -3 / 4

m₁m₂ = -1

- 3 / 4 m₂ = -1

m₂ = [tex]\frac{4}{3}[/tex]

Therefore,

x-intercept of 6

0 = 6([tex]\frac{4}{3}[/tex]) + b

b = - 8

Therefore, the equation is as follows:

y = [tex]\frac{4}{3}x-8[/tex]

learn more on x-intercept here: https://brainly.com/question/16952211

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