arielclairfl
Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Write the equation of the line perpendicular to 2x-5y=-12 that passes through the point (10,-1) in slope-intercept form.

Sagot :

Theekshana

Answer:

[tex]y=-\frac{5}{2}x-24[/tex]

Step-by-step explanation:

[tex]2x-5y=-12\\5y=2x+12\\y=\frac{2}{5}x+\frac{12}{5}\\[/tex]

if two lines perpendicular,

[tex]m_{1} .m_{2}=-1\\ \frac{2}{5} .m_{2}=-1\\m_{2}=-\frac{5}{2}[/tex]

the line perpendicular to this line is

[tex]y=-\frac{5}{2}x+k[/tex] ; k ∈ R

the line passes through the point (10,-1)

so,

[tex]-1=-\frac{5}{2} (10)+k\\-1=-25+k\\k=-24[/tex]

∴the equation of the line perpendicular to 2x-5y=-12 that passes through the point (10,-1) is

[tex]y=-\frac{5}{2}x-24[/tex]

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.