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Answered

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Write the equation of the line perpendicular to 2x-5y=-12 that passes through the point (10,-1) in slope-intercept form.

Sagot :

Theekshana

Answer:

[tex]y=-\frac{5}{2}x-24[/tex]

Step-by-step explanation:

[tex]2x-5y=-12\\5y=2x+12\\y=\frac{2}{5}x+\frac{12}{5}\\[/tex]

if two lines perpendicular,

[tex]m_{1} .m_{2}=-1\\ \frac{2}{5} .m_{2}=-1\\m_{2}=-\frac{5}{2}[/tex]

the line perpendicular to this line is

[tex]y=-\frac{5}{2}x+k[/tex] ; k ∈ R

the line passes through the point (10,-1)

so,

[tex]-1=-\frac{5}{2} (10)+k\\-1=-25+k\\k=-24[/tex]

∴the equation of the line perpendicular to 2x-5y=-12 that passes through the point (10,-1) is

[tex]y=-\frac{5}{2}x-24[/tex]

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