The displacement of the mouse is 5m and the total distance is 9m.
The given parameters;
initial displacement of the mouse = 5 m north
second displacement = 1 m South
third displacement = 3 m west
To find:
- the displacement of the mouse and the total distance it ran
Displacement is the change in the final position and the initial position of an object.
Distance is the total path covered by the object.
When the mouse was at 1 m south, the displacement = 5 m - 1m = 4m
The displacement of the mouse between 4m south and 3m west is calculated by using Pythagoras theorem.
[tex](displacement)^2 = 3^2 + 4^2\\\\(displacement)^2 = 25\\\\displacement = \sqrt{25} \\\\displacement = 5 \ m[/tex]
The total distance of the mouse = 5 m + 1m + 3m = 9m
Thus, the displacement of the mouse is 5m and the total distance is 9m.
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