Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Coordinate geometry is the use of a 2D plane to represent points.
- The transformation is a rotation of 270 degrees clockwise
- The transformation preserves length because the length of the image and preimage are the same
- The transformation preserves angles because the angles of the image and preimage are the same
Given that:
[tex]A = (-5,5) \to A' = (5,5)[/tex]
[tex]B = (-2,2) \to B' = (2, 2)[/tex]
[tex]C = (-3,2) \to C' = (2,3)[/tex]
By observing the pattern of transformation, the rule is:
[tex](x,y) \to (y,-x)[/tex]
Hence, the transformation is a rotation of 270 degrees clockwise
The length is calculated using the following distance formula:
[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2[/tex]
So, we have:
[tex]AB = \sqrt{(-5 - -2)^2 + (5 - 2)^2} =\sqrt{18[/tex]
[tex]BC = \sqrt{(-2 - -3)^2 + (2 - 2)^2} =1[/tex]
[tex]AC = \sqrt{(-5 - -3)^2 + (5 - 2)^2} =\sqrt{13[/tex]
And
[tex]A'B' = \sqrt{(5 -2)^2 + (5 - 2)^2} =\sqrt{18[/tex]
[tex]B'C' = \sqrt{(2 - 2)^2 + (2 - 3)^2} =1[/tex]
[tex]A'C' = \sqrt{(5 - 2)^2 + (5 - 3)^2} =\sqrt{13[/tex]
By comparing the lengths of the image and the preimage, we can conclude that the transformation preserves length.
The measure of the angles is calculated as follows:
[tex]a^2 = b^2 + c^2 -2ab \cos A[/tex]
So, we have:
[tex]18 = 1 + 13 -2 \times 1 \times \sqrt{13} \cos C[/tex]
[tex]18 - 1 - 13= -2 \times 1 \times \sqrt{13} \cos C[/tex]
[tex]4= -2 \times 1 \times \sqrt{13} \cos C[/tex]
[tex]-2= \sqrt{13} \cos C[/tex]
Make cos C the subject
[tex]\cos C = -0.5547[/tex]
[tex]C = cos^{-1}(-0.5547)[/tex]
[tex]C = 124^o[/tex]
Also, we have:
[tex]\frac{a}{\sin A} =\frac{c}{\sin C}[/tex]
So, we have:
[tex]\frac{1}{\sin A} =\frac{\sqrt{18}}{\sin( 124)}[/tex]
[tex]\frac{1}{\sin A} =5.1175[/tex]
Rewrite as:
[tex]\sin A = \frac{1}{5.1175}[/tex]
[tex]\sin A = 0.1954[/tex]
[tex]A = \sin^{-1}(0.1954)[/tex]
[tex]A = 11^o[/tex]
Also, we have:
[tex]A + B + C = 180^o[/tex] --- sum of angles in a triangle
[tex]11 + B + 124 = 180^o[/tex]
Collect like terms
[tex]B = 180 -11 - 124[/tex]
[tex]B = 45[/tex]
Hence:
[tex]\angle A = 11[/tex] [tex]\angle B = 45[/tex] and [tex]\angle C = 124[/tex]
Read more about coordinate geometry at:
https://brainly.com/question/1601567
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.