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Sagot :
Answer:
Given:
- g(x)= 2x² - 3x + 19
Evaluate each value:
A)
- g(0) =
- 2(0)² - 3(0) + 19 =
- 19
B)
- g(-1) =
- 2(-1)² - 3(-1) + 19 =
- 2 + 3 + 19 =
- 24
C)
- g(3) =
- 2(3)² - 3(3) + 19 =
- 18 - 9 + 19 =
- 28
D)
- g(-x) =
- 2(-x)² - 3(-x) + 19 =
- 2x² + 3x + 19
E)
- g(1 - t) =
- 2(1 - t)² - 3(1 - t) + 19 =
- 2(1 - 2t + t²) - 3 + 3t + 19 =
- 2t² - 4t + 2 + 3t + 16 =
- 2t² - t + 18
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