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Given that g(x)= 2x^2 - 3x + 19, find each of the following. A.) g(0) B.) G (-1) C.) g(3) D.)g(-x) E.) G (1-t)

Sagot :

mhanifa

Answer:

Given:

  • g(x)= 2x² - 3x + 19

Evaluate each value:

A)

  • g(0) =
  • 2(0)² - 3(0) + 19 =
  • 19

B)

  • g(-1) =
  • 2(-1)² - 3(-1) + 19 =
  • 2 + 3 + 19 =
  • 24

C)

  • g(3) =
  • 2(3)² - 3(3) + 19 =
  • 18 - 9 + 19 =
  • 28

D)

  • g(-x) =
  • 2(-x)² - 3(-x) + 19 =
  • 2x² + 3x + 19

E)

  • g(1 - t) =
  • 2(1 - t)² - 3(1 - t) + 19 =
  • 2(1 - 2t + t²) - 3 + 3t + 19 =
  • 2t² - 4t + 2 + 3t + 16 =
  • 2t² - t + 18

sorry if is wrong,..........;

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View image shanikaconder42
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