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What is the midpoint of segment AB when A is at (5,7) and B is at (3,1)?

Sagot :

The formula for the midpoint is:

(x1 + x2)/2, (y1 + y2)/2

Midpoint = (5+3)/2 , (7+1)/2

Midpoint = 8/2 , 8/2

Midpoint =(4,4)

Answer:

(4, 4)

Step-by-step explanation:

A (5,7) and B (3,1)

To find the midpoint of a line segment, use this formula.

[tex]midpoint =(\frac{x^1+x^2}{2} ,\frac{y^1+y^2}{2} )[/tex]

(x1, y1) = coordinates of first point

(x^2, x^2) = coordinates of second point.

Basically, you add the coordinates x^1 and x^2, then divide the sum by 2. That would be your first coordinate.

Next, you add y^1 and y^2, then divide the sum by 2. That would be your second coordinate.

[tex]midpoint-(\frac{5+3}{2} ,\frac{7+1}{2})[/tex]

[tex]midpoint = (4, 4)[/tex]

Therefore, the midpoint of segment AB is (4,4).

Let me know if you have any further questions.

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