lisa847
Answered

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factor each completely x^3^a -27y^6^B

Pls need help
From: Brainly.ph (Philippine's)​

Sagot :

Tasyha

Answer:

[tex] = ( {x}^{a} - {3y}^{2b} ) \times ( {x}^{2a} + {3x}^{a} {y}^{2b} + {9y}^{4b} )[/tex]

Step-by-step explanation:

[tex] {x}^{3a} - 27 {y}^{6b} [/tex]

[tex]( {x}^{a} {)}^{3} - {3}^{3} \times ( {y}^{2b} {)}^{3} [/tex]

[tex]( {x}^{a} {)}^{3} - (3 {y}^{2b} {)}^{3} [/tex]

[tex]( {x}^{a} - {3y}^{2b} ) \times (( {x}^{a} {)}^{2} + {x}^{a} \times {3y}^{2b} + ( {3y}^{2b} {)}^{2} )[/tex]

[tex] \boxed{\green{= ( {x}^{a} - {3y}^{2b} ) \times ( {x}^{2a} + {3x}^{a} {y}^{2b} + {9y}^{4b})}} [/tex]

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