Given that the radius of a silver atom is 145 pm, it would take [tex]7.97 \times 10^{6}[/tex] silver atoms laid side by side to span a distance of 2.31 mm.
The radius of a silver atom is 145 pm. Then, the diameter (twice the radius) is:
[tex]d = 2 \times 145 pm = 290 pm[/tex]
We will convert 290 pm to millimeters. We will use the conversion factors:
[tex]290 pm \times \frac{1m}{10^{12}pm } \times \frac{10^{3}mm }{1m} = 2.90 \times 10^{-7} mm[/tex]
If the diameter of 1 silver atom is 2.90 × 10⁻⁷ mm, the number of silver atoms required to span a distance of 2.31 mm is:
[tex]2.31 mm \times \frac{1Ag\ atom}{2.90 \times 10^{-7}mm } = 7.97 \times 10^{6} Ag\ atom[/tex]
[tex]7.97 \times 10^{6}[/tex] silver atoms span a distance of 2.31 mm.
You can learn more about unit conversions here: brainly.com/question/19420601
