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Lisa is standing on a dock beside a lake. She drops a rock from her hand into the lake. After the rock hits the surface of the lake, the rock's distance from the lake's surface changes at a rate of βˆ’2 inches per second. If Lisa holds her hand 5 feet above the lake's surface, how far from Lisa's hand is the rock 4 seconds after it hits the surface?

Sagot :

mhanifa

Answer:

  • 5 ft 8 in or 68 in

Step-by-step explanation:

In 4 seconds the rock will be at:

  • 2*4 = 8 in from the surface

Add 5 feet to this to get the required distance:

  • 5 ft + 8 in = 5*12 in + 8 in = 68 in

Distance after 8s:-

[tex]\\ \rm\longmapsto 4(-2)=-8in[/tex]

Now

Distance:-

[tex]\\ \rm\longmapsto 5-(-8)[/tex]

[tex]\\ \rm\longmapsto 5ft+8in[/tex]

  • 1ft=12in

[tex]\\ \rm\longmapsto 5ft+3/4ft[/tex]

[tex]\\ \rm\longmapsto 23/4ft[/tex]

[tex]\\ \rm\longmapsto 5.7ft[/tex]

  • Convert to in

[tex]\\ \rm\longmapsto 5.7\times 12[/tex]

[tex]\\ \rm\longmapsto 68in[/tex]

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