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Sagot :
We have that it takes the ball [tex]t=0.553sec[/tex] to take to hit the ground
[tex]t=0.553sec[/tex]
From the Question we are told that
Initial height [tex]s=1.5m[/tex]
Generally the equation for Time is mathematically given as
[tex]S=ut+1/2at^2\\\\1.5=0.5*9.8[/tex]
[tex]t=0.553sec[/tex]
For more information on this visit
https://brainly.com/question/22271063?referrer=searchResults
The paper ball will hit the ground from 1.5 m at 0.55 s.
Here we can use the free fall kinematics equations. Let's see that the paper ball falls from the rest, so the initial velocity will be 0.
[tex]y=y_{i}+v_{i}t-0.5gt^{2}[/tex]
Here:
- y is the final height
- y(i) is the initial height
- v(i) initial velocity (will be 0)
- g is the gravity (9.81 m/s²)
- t the time
Now, the initial height will be 1.5 m, putting our reference system zero in the ball. So, the final height will be 0 m, because it hits the ground.
[tex]0=1.5-0.5(9.81)t^{2}[/tex]
Therefore, we just need to solve it for t.
[tex]t=\sqrt{\frac{3}{9.81}}[/tex]
[tex]t=0.55\: s[/tex]
The ball will hit the ground at 0.55 s.
You can learn more about free fall motion here:
https://brainly.com/question/17610229
I hope it helps you!
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