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Your physics teacher crumples a piece of paper into a ball and releases it from
rest 1.5 m from the ground. How long does the ball take to hit the ground?

Sagot :

okpalawalter8

We have that it takes the ball [tex]t=0.553sec[/tex] to take to hit the ground

[tex]t=0.553sec[/tex]

From the Question we are told that

Initial height [tex]s=1.5m[/tex]

Generally the equation for Time  is mathematically given as

[tex]S=ut+1/2at^2\\\\1.5=0.5*9.8[/tex]

[tex]t=0.553sec[/tex]

For more information on this visit

https://brainly.com/question/22271063?referrer=searchResults

whitneytr12

The paper ball will hit the ground from 1.5 m at 0.55 s.

Here we can use the free fall kinematics equations. Let's see that the paper ball falls from the rest, so the initial velocity will be 0.

[tex]y=y_{i}+v_{i}t-0.5gt^{2}[/tex]

Here:

  • y is the final height
  • y(i) is the initial height
  • v(i) initial velocity (will be 0)
  • g is the gravity (9.81 m/s²)
  • t the time

Now, the initial height will be 1.5 m, putting our reference system zero in the ball. So, the final height will be 0 m, because it hits the ground.

[tex]0=1.5-0.5(9.81)t^{2}[/tex]

Therefore, we just need to solve it for t.

[tex]t=\sqrt{\frac{3}{9.81}}[/tex]

[tex]t=0.55\: s[/tex]

The ball will hit the ground at 0.55 s.

You can learn more about free fall motion here:

https://brainly.com/question/17610229

I hope it helps you!

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