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calculate the number of atoms present in 1.4g of N² molecule​

Sagot :

rspill6

Answer:  6.02x10^22 atoms

Explanation:  1.4 grams is (1.4g/28 g/mole) = 0.05 moles of N2.

(0.05 moles)*(6.02x10^23 molecules/mole) = 3.01x10^22 molecules

(3.01x10^22 molecules)(2 atoms/molecule) = 6.02x10^22 atoms

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