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Michael rotates ABC to form the image A'B'C'. The table shows the corresponding vertices for ABC and AA'B'C'. What degree of rotation and direction did Michael rotate ABC to form AA'B'C'? ДАВС A (2,3) B(4,4) C(3,0) LA'B'C' A'(3,-2) B'(4,-4) C'(0, -3)​

Sagot :

Answer:

90 degree rotation in the clockwise direction.

Step-by-step explanation:

Point A transforms to A'

- that is x coordinate: 2 ---> 3

and y coordinate   3 ---> -2

So the rotation is clockwise from Quadrant1 to Quadrant 4.

The slope of OA = 3/2 and the slope of OA' = -2/3.

The product of these slopes = 3/2 * -2/3 = -1 so the lines are perpendicular - that is the line has passed through an angle of 90 degrees.

A similar result occurs if we consider points B, C and D.

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