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Sagot :
3(2a - 2) = 2(3a - 3)
6a - 6 = 6a - 6
6a - 6a = -6 + 6
0 = 0
Answer: all reel numbers are solutions
[tex]\\ \sf\longmapsto 3(2a-2)=2(3a-3)[/tex]
[tex]\\ \sf\longmapsto 6a-6=6a-6[/tex]
[tex]\\ \sf\longmapsto 6a-6-6a+6=0[/tex]
[tex]\\ \sf\longmapsto 0=0[/tex]
Hence
[tex]\\ \sf\longmapsto a\epsilon R[/tex]
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