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8(sin⁶p + cos⁶p) = 5+3cos4p​

Sagot :

Answer:

this is going to be alot i am very sorry. i had to put it like that im sorry

Step-by-step explanation:

As

a

3

+

b

3

=

(

a

+

b

)

(

a

2

+

b

2

a

b

)

8

(

sin

6

P

+

cos

6

P

)

=

8

(

sin

2

P

+

cos

2

P

)

(

sin

4

P

+

cos

4

P

sin

2

P

cos

2

P

)

=

8

(

sin

4

P

+

cos

4

P

+

2

sin

2

P

cos

2

P

3

sin

2

P

cos

2

P

)

=

8

(

(

sin

2

P

+

cos

2

P

)

2

3

sin

2

P

cos

2

P

)

=

8

(

1

3

4

(

4

sin

2

P

cos

2

P

)

)

=

8

6

sin

2

2

P

=

8

6

(

1

cos

2

2

P

)

=

2

+

6

cos

2

2

P

As

cos

4

P

=

2

cos

2

2

P

1

, we have

cos

2

2

P

=

1

+

cos

4

P

2

Hence,  

8

(

sin

6

P

+

cos

6

P

)

=

2

+

6

×

1

+

cos

4

P

2

=

2

+

6

2

+

3

cos

4

P

=

5

+

3

cos

4

P