Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
From the pycnometer that weighs 20.455g empty and 31.486g when filled with water at 25oC; we can infer that the density of the alloy in this system is 7.89 g/mL
From the parameters given;
- the mass of an empty pycnometer = 20.455 g
- when the pycnometer is filled with water, the mass = 31.486 g
To determine the mass of the water, we have:
- Mass of water = mass of pycnometer with water - mass of empty pycnometer
- Mass of water = (31.486 - 20.455) g
- Mass of water = 11.031 g
However, we need to find the volume of the water, since density is given as 0.99704 g/mL
Now, using the relation:
[tex]\mathbf{Density = \dfrac{mass}{volume}}[/tex]
[tex]\mathbf{0.99704 g/mL = \dfrac{11.031 g}{volume}}[/tex]
[tex]\mathbf{volume = \dfrac{11.031 \ g}{0.99704 \ g/mL}}[/tex]
[tex]\mathbf{volume \ of \ water = \dfrac{11.031 \ g}{0.99704 \ g/mL}}[/tex]
volume of water = 11.064 mL
Since the volume of the water is equivalent to the volume of the pycnometer;
- we can infer that the volume of the pycnometer = 11.064 mL
Similarly, given that:
- mass of pycnometer and alloy = 28.695 g
- mass of the entire system (i.e. pycnometer, alloy & water) = 38.689 g
∴
- Mass of the water = 38.689 g - 28.695 g
- Mass of the water = 9.994 g
Here, from the entire system, the volume of the water again is calculated as follows:
[tex]\mathbf{Density = \dfrac{mass}{volume}}[/tex]
[tex]\mathbf{0.99704 g/mL = \dfrac{9.994 g}{volume}}[/tex]
[tex]\mathbf{volume = \dfrac{9.994 \ g}{0.99704 \ g/mL}}[/tex]
[tex]\mathbf{volume \ of \ water = \dfrac{11.031 \ g}{0.99704 \ g/mL}}[/tex]
Volume of water = 10.02 mL
Finally, by applying the volume of the pycnometer as well as the volume of the water to determine the volume of the alloy, we have:
- Volume of alloy = volume of pycnometer - volume of water
- Volume of alloy = 11.064 mL - 10.02 mL
- Volume of alloy = 1.044 mL
Recall that:
- the mass of the empty pycnometer = 20.455 g, and;
- the mass of the pycnometer and alloy = 28.695 g
From the parameters above, we can deduce the mass of the alloy as follows;
Mass of alloy = 28.695 g - 20.455 g
Mass of alloy = 8.24 g
We know now that:
[tex]\mathbf{Density = \dfrac{mass}{volume}}[/tex]
∴
[tex]\mathbf{Density \ of \ the \ alloy = \dfrac{8.24 \ g}{1.044 \ mL}}[/tex]
Density of the alloy = 7.89 g/mL
Therefore, from the above calculation, we can conclude that the density of the alloy = 7.89 g/mL
Learn more about density, mass and volume here:
https://brainly.com/question/24386693?referrer=searchResults
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
