Puppylover05
Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Jason is pulling a box across the room. He is pulling with a force of 27 newtons and his arm is making a 49 angle with the horizontal, what is the horizontal component of the force he is pulling with?

Sagot :

Force=27N

Angle=49

Vertical componenets:-

[tex]\\ \sf\longmapsto Fsin\theta[/tex]

[tex]\\ \sf\longmapsto 27sin49[/tex]

[tex]\\ \sf\longmapsto 27(0.7)[/tex]

[tex]\\ \sf\longmapsto 18.9N[/tex]

ferrybukantoro

Answer:

17.712 newtons

Step-by-step explanation:

the horizontal component of the force = Fh

Fh = F. cos 49°

= 27. (0.656)

= 17.712 newtons

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.