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m∠DFG=(2x+6)° and m∠EFG=(3x−11)°. Find the value of x.

Sagot :

The corresponding angles between parallel lines and a transversal are equal. The value of x is 17

Given that:

[tex]\angle DFG = (2x +6)^o[/tex]

[tex]\angle EFG = (3x -11)^o[/tex]

From the complete question, both angles are corresponding angles.

This means that they are congruent

So:

[tex]\angle EFG = \angle DFG[/tex]

This gives:

[tex](3x -11)^o=(2x + 6)^o[/tex]

[tex]3x -11 = 2x + 6[/tex]

Collect like terms

[tex]3x - 2x = 11 + 6[/tex]

[tex]x = 17[/tex]

Hence, the value of x is 17

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