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Between 9 P.M. and 6:20 A.M. , the water level in a swimming pool decreased by 7 (1)/(2) in
. Assuming that the water level decreased at a constant rate, how much did the water level drop each hour?

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Answer:

Step-by-step explanation:

The hourly drop between the two times is 1/40

Firstly, we need to find the difference in time between 9 pm and 6:36 am

That would be 9 hours and 36 minutes

It would be needed to convert 36 minutes to hours

Mathematically, 60 minutes = 1 hour

So 36 minutes = (36 * 1)/60 = 36/60 = 0.6

So the difference between the two time is simple 9.6 hours

So the total drop during the time is given by 6/25

So the hourly drop will be 6/25 divided by 9.6

= 6/25 * 1/9.6 = 6/240 = 1/40

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