pie65879
Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

WILL GIVE BRAINLEST 100Pts
ANSWER ALL QESTIONS PLS!!!!!!!!!!!!!!!!
A.Write the algebraic expressions representing the length and with of Marlene's house.

B.Write the algebraic expression representing the perimeter of Marlene's house in simplest form

C.If the perimeter is 142 feet, find the value of x.
22. Use the information from Question 21. Show how the Distributive Property can be used to find the area of Marlene's living room.

23 Use the algebraic expression for length and width of Marlene's living room found in the diagram and the value of x found in Question 21C

A.find the actual length and width of her living room.

B. Find the actual area of Marlene's living room use actual dimensions

24. Using the algebraic expression for the area found in Questions 22B, find the area of the living room.

25. Are your answers to Question 23B and Qestions 24 the same? What can you conclude?

Sagot :

syedamaimuna9a6

Answer:

A .

length : 2x + 2 + x - 4 + x-2

        =  2x + 2 + - 4 + x-2

         = 2x + x - 4 + x - 2

         = 4x -6

width :  x - 2 + x

         = 2x -2

B.

to find the perimeter

perimeter of rectangle = 2 ( l + b)

                                      = 2  (4x -6 + 2x -2)

                                      = 2 ( 6x - 8)

                                      = 12x - 16

perimeter of Marlene's house in simplest form is 12x - 16

C.

perimeter = 142  finding the value of x ..

142 = 12x - 16

12x = 142 + 16

12x = 158

x = 158/12

x = 13.16

22.

area of living room = length × breadth

                               = 2x + 2 ×x

                                = 2 (13.16) + 2 × 13.16 (distributive property used)

                                = 26.32 + 2 × 13.16

                                = 28.32 × 13.16

                                = 372.6912

area of her living room = 372.6912

23. to find the length and width of Marlene's living room

length = 2x + 2

            = 2 (13.16) + 2

            = 26.32 + 2

            = 28.32

Width = x

          = 13.16

A .

The actual length of her living room is  28.32

The actual width of her living room is 13.16

B.

The actual area of Marlene's Living room is 372.6912 feet (given above) using actual dimensions

24.

Actual area of living room = length × breadth

                                = 2x + 2 ×x

                                = 2 (13.16) + 2 × 13.16 (distributive property used)

                                = 26.32 + 2 × 13.16

                               = 28.32 × 13.16

                                = 372.6912

Actual area of her living room = 372.6912

25.

Yes the answers to Question 23B and Qestions 24 are same .

We can conclude by saying that the x value doesn't change

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.