Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

When wile coyote is launched his velocity is 20 m/s. As a slightly underweight 10kg coyote, how far would the 400 N/m spring have been stretched to give him this speed?

Sagot :

Answer:

E = 1/2 m v^2 = 1/2 k x^2     equating KE of coyote and spring

x^2 = m v^2 / k = 10 kg * 20^2 m^2 / s^2 / 400 N / m

x^2 = 10 * 400 / 400 (kg m^3 / kg-m) = 10 m^2

x = 3.16 m

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.